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	<title>智慧上进·限时特训·分钟·分科模拟卷理科 &#8211; 答案星辰</title>
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		<title>2022届智慧上进·限时特训·40分钟·分科模拟卷(一)1理科数学答案</title>
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		<pubDate>Wed, 23 Mar 2022 23:44:03 +0000</pubDate>
		<dc:creator><![CDATA[yun]]></dc:creator>
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		<description><![CDATA[6.【答案】D【解析】依题意，f(x-1)+f(1+x)=0,f(x)=f(-x),则函数f(x)的周期为4；而f(0)=2,令x=1,得f(0)+f(2)=0,故f(2)=-2;令x=0,得2f(1)=0,解得f(1)=0,故f(-1)=0,故f(3)=0,故f(1)+f(2) [&#8230;]]]></description>
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		<title>2022届智慧上进·限时特训·40分钟·分科模拟卷(三)3理科数学答案</title>
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		<pubDate>Wed, 23 Mar 2022 23:22:24 +0000</pubDate>
		<dc:creator><![CDATA[yun]]></dc:creator>
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		<description><![CDATA[9.解：(1)证明：过E向BC作垂线，垂足为G,连接FG ∵AC⊥平面PABD,又PA⊥AB,∴PA⊥平面ABC ∴PA⊥BC,PA//EG,(2分) 又CE:ED=AF:FB=GC:BG,∴GF∥AC,且GFnEG=G,(3分) ∴平面EFG//平面PAC 即证EF/平面PAC [&#8230;]]]></description>
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